This article provides a sample solution for Calculating Statistical Analysis.
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For this exercise, use the attached dataset to complete the following:
Calculate the mean, median, mode and standard deviation for temperatures by sorting for Latitude 3.
Conduct a hypothesis testing for temperatures in Latitude 1. A two-tailed hypothesis test for a single sample t-test. Report reject or retain the null, and interpret what the results indicate.
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Solution
Calculating Statistical Analysis
Question 1
From the dataset, temperature 3 had the following descriptive statistics after its analysis; the mean was 28.6, Mode at 25, Median was 28.5 and standard deviation was 2.674987.
Question 2
H0: The temperature value in latitude 1 is insignificant.
H1: The temperature value in latitude 1 is significant.
Temperature 1 had the following inference on its test of hypothesis
| Mean | 9.275362319 |
| Variance | 168.4083546 |
| Observations | 69 |
| df | 68 |
| t Stat | -3.331449471 |
| P(T<=t) one-tail | 0.00069979 |
| t Critical one-tail | 1.667572281 |
| P(T<=t) two-tail | 0.00139958 |
| t Critical two-tail | 1.995468931 |
Since the analysis were done one a one sample two tailed test, the t calculated value is
-3.331449471 with the T critical value being 1.995468931. This leads to rejection of the null hypothesis since the absolute t calculated is greater than t critical.
The p value is 0.00139958 which is less than the alpha value of 0.05, this leads to the decision to reject the null hypothesis.
A conclusion is therefore made that the temperature value in latitude 1 are all significant in the dataset.
Question 3
H0: The mean temperature in all locations is not equal to 14.48
H1: The mean temperature in all locations is equal to 14.48
| Mean | 14.4787234 |
| Variance | 208.7468543 |
| Observations | 94 |
| Hypothesized Mean | 14.48 |
| df | 93 |
| t Stat | -0.000856658 |
| P(T<=t) one-tail | 0.49965916 |
| t Critical one-tail | 1.661403674 |
| P(T<=t) two-tail | 0.999318321 |
| t Critical two-tail | 1.985801814 |
As you continue, thestudycorp.com has the top and most qualified writers to help with any of your assignments. All you need to do is place an order with us. (Calculating Statistical Analysis)
The analysis were done one a two tailed test, the t calculated value is -0.000856658 with the T critical value being 1.985801814. This leads to failure to reject the null hypothesis since the absolute t calculated is less than t critical.
The p value is 0.999318321 which is greater than the alpha value of 0.05, this leads to the decision to fail to reject the null hypothesis.
A conclusion is therefore made that the temperature value in all the locations is not equal to 14.48.
Question
For this exercise, use the attached dataset to complete the following:
- Calculate the mean, median, mode and standard deviation for temperatures by sorting for Latitude 3.
- Conduct a hypothesis testing for temperatures in Latitude 1. A two-tailed hypothesis test for a single sample t-test. Report reject or retain the null, and interpret what the results indicate.
- The average temperature for all locations is 14.48 degrees.
- Test to see if the temperature is different from 14.48 degrees.